Question

An object 1cm high is placed at 0.20 m
from a convex lens of the Focal length
0.15m, the image
position and height are​

Answer 1

Answer:

Given:u=−10cm               f=20cm        (convex lens)

To find: v and image's nature.

Solution: From lens formula

v1−u1=f1

v1+101=201

v1=20−1

v=−20cm

And magnification = uv=2

Hence image formed is virtual, erect and magnified two times.

Answer 2

I DONT KNOW. the answer byee