Question

An object 1cm high produces a real image 1.5cm high, when placed at a distance of 15cm from a concave mirror.calculate : (1) the position of the image (2) focal length of the concave mirror​

Answer 1

Explanation:

here yours answer

Answer 2

Explanation:

height of object (h1):. 1cm

height of image (h2): -1.5cm

object distance (u): -15cm

1. To find the position of the image we need to find v

so,

h2/h1= -v/u

-1.5/1 = -v/-15 (cross multiplication)

-22.5=v

2. To find focal lenght

1/f = 1/v+1/u

1/f= 1/-22.5+1/-15

f= -9

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