Physics, asked by dipeshchadgal7664, 1 year ago

An object 2.6cm high is 24cm from a concave mirror whose radius of curvature is 16cm. Determine (i) the location of its image, and (ii) size and nature of the image.

Answers

Answered by vbhalla230
0

Answer:

the object is located at 6cm from the mirror between c and f. The height of the image is 0.65cm and its nature is real, invert and diminished.

Explanation:

u=-24 h=2.6 f=8

1/f=1/v+1/u

1/v=1/8+1/24

v=6cm

h/h'=-u/v

2.6/h'=24/6

h' = 2.6/4=0.65

Similar questions