An object 2.6cm high is 24cm from a concave mirror whose radius of curvature is 16cm. Determine (i) the location of its image, and (ii) size and nature of the image.
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Answer:
the object is located at 6cm from the mirror between c and f. The height of the image is 0.65cm and its nature is real, invert and diminished.
Explanation:
u=-24 h=2.6 f=8
1/f=1/v+1/u
1/v=1/8+1/24
v=6cm
h/h'=-u/v
2.6/h'=24/6
h' = 2.6/4=0.65
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