an object 2 centimetre is placed at a distance of 5 cm from a concave mirror of focal length 10 cm. find out the position magnification and nature of the image
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Height of object = 2cm
Object distance = 15cm
Focal length = 10cm
1/f = 1/v +1/u
-1/10 = -1/15 +1/v
1/v = -3 +2 /30
v = -30 cm
Height of image/Height of object = -v /u
Height of image / 2 = 30/-15
Height of image = - 4cm
Nature - Real and inverted
Position - 30 cm from concave mirror
Size = 4 cm....
HOPE IT WILL HELP YOU
Object distance = 15cm
Focal length = 10cm
1/f = 1/v +1/u
-1/10 = -1/15 +1/v
1/v = -3 +2 /30
v = -30 cm
Height of image/Height of object = -v /u
Height of image / 2 = 30/-15
Height of image = - 4cm
Nature - Real and inverted
Position - 30 cm from concave mirror
Size = 4 cm....
HOPE IT WILL HELP YOU
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