an object 2 cm high is placed at a distance of 16 cm from a concave mirror which produces a real image 3cm option first what is the focal length of the second find the position of the image
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Explanation:
size of the object = h1 = 2 cm
size of the image = h2 = -3 cm
u = obj distance = -16 m
Therefore from formula -v/u = h2 / h1, we have
-v/(-16) = -3/2
v/16 = -3/2
v = -3* 16/2
v = - 24 cm
From mirror formula = 1/v + 1/u = 1/f
=> 1/-24 + 1/-16 = 1/f
=> 1/f = (-2 - 3)/ 48
=> 1/f = -5 / 48
=> f = - 48/5
= > f = - 9.6 cm
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