Question

An object 2 cm in size is placed 20 cm in front of a concave mirror of focal length 10
cm. Find the distance from the mirror at which a screen should be placed in order to
obtain a sharp image. What will be the size and nature of the image formed?​

Answer 1

Answer:

image distance (v)= +20

Image height (h') = -2

Magnification (m)= -1

Object height (h) =+2cm

Object distance (u) = -20cm

Focal length (f) =+10cm

Using formula,

1/f=1/v-1/u

=1/10=1/v-(-1/20)

=I/v=1/10-1/20

=2-1/20

=1/20

V=+20

Using magnification formula,

M=h'/h=v/u

h'=h(v/u)

h'=2(20/-20)

h'=-2

M=v/u

M=-20/20

M= -1

Nature of the image=real and inverted

Size of the image=same size

Position of the image= at 2f1 (c)

Explanation:

Answer 2

here answer is v= -20 and height of image is - 2 . real and inverted