An object 20 centimetre tall is placed on the principal axis of a convex lens is 30cm image is formed at a distance of 10 cm from the lens calculate focal length of the lens
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height of object , h=20cm
height of image ,h'=30 cm
image distance ,v=10cm
magnification m=v/u=h'/h
10/u=30/20
u=10*2/3
u=6.66666666667
then lens formula =1/f=1/v-1/u
1/f=1/10-1/6.66
f=-0.050cm
Answered by
0
m= -v/u = h1/h
-10/u = 30/20
-10 x 2/3 = u
-20/3 = u
using lens formula;
1/f = 1/v - 1/u
= 1/10 + 3/20
= 2 + 3/ 20
= 5/20
1/f = 1/4
therefore, f = +4
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