an object 2cm in height is placed at a distance 16cm from a concave mirror.If the focal lenght of the mirror is 9.6cm,find the image distance,nature and size of the image
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given:- h=2cm
u= -16cm
f= -9.6cm
v=? and h'=?
using mirror formula we get that 1/f-1/u=1/v
1/-9.6 - (1/-16) =1/v
10/-96 + 1/16 =1/v (lcm=96)
-10+6/96 = -4/96
1/v= -1/24
therefore, v= -24cm
using magnification formula:- h'/h= -v/u
h'= -v*h/u
h'= -(-24)x 2/ -16
= 24x2/-16 = 3
hence, height of image (h')= 3cm and image distance(v)= -24cm
hope it helps u !! :)
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