An object 2cm long placed 40cm in front of a concave mirror of a focal length 15cm find the size of the image
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Object-size, h = + 2.0 cm;
Object-distance, u = – 40.0 cm;
Focal length, f = –15.0 cm;
Image-distance, v = ?
Image-size, h′ = ?
Mirror formula is (1/v) + (1/u) = 1/f
1/v = (1/f) − (1/u)
= (−1/15) + (1/40.0)
= −5/120
v = − 24cm.
The screen should be placed at 24 cm from the mirror. The image is real.
Magnification m = h'/h = − v/u =- 24 /(– 40) = – 1.67
Height of the image h' = mh = (– 1.67)2 = − 3.3 cm
The image in inverted and enlarged.
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