Question

An object 2cm tall stand on the principal axis of a convering lens of focal length 8cm. Find the position, nature and size of the image formed if the object is at 12cm from the lens.​

Answer 1

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Answer 2

h1 = 2 cm

f = 8 cm

(i) u = -12 cm

Lens formula: 1/v – 1/u = 1/f

1/v – 1/-12 = 1/8

1/v = 1/24

V = 24 cm

Image is 24 cm behind the lens.

m = v/u = h2/h1

24/-12 = h2/2

h2 = -4 cm

(ii) u = - 6 cm

Lens formula : 1/v – 1/u = 1/f

1/v – 1/-6 = 1/8

1/v = - (1/24)

V = -24 cm

Image is 24 cm in front of the lens.

m = v/u = h2/h1

-24/-6 = h2/2

h2 = 8 cm

Image is 8 cm high, virtual and erect.