Question

An object 2mm high kept at a distance 6cave cm from a concave mirror produce a real image 1 cm high find the position of image and focal lengthof the mirror

Answer 1

Answer:

F=-20cm

ho=4cm

hi=?

u=-60cm

by using mirror formula

1/f=1/v+1/u

1/-20=1/v+1/-60

1/-20=1/v-1/60

1/-20+1/60=1/v

-3+4/60=1/v

-30=v

by ising manification formula

m=-v/u

m=30/-60

m=1/-2

then

m=hi/ho

1/-2=hi/4

4/-2=hi

-2=hi means height of the image.

nature is real, inverted and smaller than the object size.