Question

an object 3 cm high is placed at a distance of 8 cm from a concave mirror which produces a virtual image 4.5 cm what is the focal length of the mirror and what is the position of the im​

Answer 1

Answer

m = -v/u = hi/ho

     -4.5/-8 =  hi/3

        -13.5/-8  = hi

            1.68cm = hi

Therefore, height of image is 1.68cm

The question is wrong as concave mirror always produces enlarged virtual image and enlarged real image of an object. In this case height of object is 3cm and height of image is 1.68cm which is wrong.

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