Question

an object 3 cm high is placed at a distance of 9 cm in front of concave mirror of focal length 18cm. find the position, nature and size

Answer 1

hope it helps ask if you don't understand

Answer 2

Answer:

Hey !! ^_^

Here is your answer

⬇️⬇️⬇️⬇️⬇️⬇️⬇️

Size of object(o) = 3cm

Distance of object (u) = -9cm ( sign convention)

focal length(f) = -18cm ( sign convention)

Mirror Formula

1/f = 1/v + 1/u

1/v = 1/f - 1/u

putting the value

1/v = 1/(-18) - 1/(-9)

1/v = 1/(-18) + 1/9

1/v = (-1 + 2)/18

1/v = 1/18

v = 18.( + sign indicate that the image is formed behind the mirror)

The position of image is behind the mirror 18 cm far from the pole

m = v/u

m = 18/9

m = 2

The size of image is 2 times larger than object or magnified

or ...

m = I/O

2 = I/3

I = 3 × 2

I = 6

Image will be virtual and erect

Thank you ✌️☺️