Social Sciences, asked by xxitsshivangixx, 9 hours ago

an object 30 cm in size is placed at 20cm in front of concave mirror of focal lenght 12 CM at what distance from the mirror should a screen be placed order to obtain a sarp image find the nature and size of the image​

Answers

Answered by meandnisha12345
1

Hope it will help u

EXPLANATION:

According to the question:

Object distance, u=−30 cm

Focal length, f=−15 cm

Let the Image distance be v.

By mirror formula:

v

1

+

u

1

=

f

1

[4pt]

v

1

+

−30 cm

1

=

−15 cm

1

[4pt]

v

1

=−

−30 cm

1

+

−15 cm

1

[4pt]

v

1

=

30 cm

1−2

[4pt]

v

1

=−

30 cm

1

[4pt]

∴v=−30 cm

Thus, screen should be placed 30 cm in front of the mirror (Centre of curvature) to obtain the real image.

Now,

Height of object, h

1

=2 cm

Magnification, m=

h

1

h

2

=−

u

v

Putting values of v and u:

Magnification m=

2 cm

h

2

=−

−30 cm

−30 cm

2 cm

h

2

=−1

[4pt];

⇒h

2

=−1×2 cm=−2 cm

Thus, the height of the image is 2 cm and the negative sign means the image is inverted.

Thus real, inverted image of size same as that of object is formed.

The diagram shows image formation.

Answered by rd318835
1

Explanation:

Image position = -30cm . at C

Nature of image is real and inverted

size = same size

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