An object 3cm high is placed at a distance of 10 cm in front of a converging mirror of focal length 20 cm. Find the position, nature and size of the image formed.
Answers
Answered by
397
Given,
height of the object = 3cm
object distance = 10cm
focal length = 20cm
NOW,
According to Mirror formula,
1/f = 1/u + 1/v
1/v = -1/20 - (-1/10)
= -1/20 + 1/10
= (-1+2)/20
= 1/20
v = 20cm
NOW,
-v/u = h(I)/h(o)
-20/-10 = h(I)/ 3
h(I) = 2×3
h(I) = 6 cm
height of the object = 3cm
object distance = 10cm
focal length = 20cm
NOW,
According to Mirror formula,
1/f = 1/u + 1/v
1/v = -1/20 - (-1/10)
= -1/20 + 1/10
= (-1+2)/20
= 1/20
v = 20cm
NOW,
-v/u = h(I)/h(o)
-20/-10 = h(I)/ 3
h(I) = 2×3
h(I) = 6 cm
ayush521:
mast yar
please mark as brainliest
Please tell me that why u've taken focal length negative
Answered by
73
Answer:-
Nature- Virtual and erect
Position- The image is formed at a distance of 20 cm behind the mirror.
Size- Image size is 6 cm
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