an object 3cm high is placed at a distance of 8cm from a concave mirror which produces a virtual image of 4.5cm,,, draw ray diagram and explain it
Answers
Given.
height of object = 3cm = H object
the object distance = - 8cm (object distance is always negative)
if the concave mirror produces an image of 4.5cm that means that
⇒ height of image = 4.5cm = H image
magnification = m = hi/ho = -v/u
= 4.5/3 = -(v)/-8cm
= 4.5 × 8 / 3 = v
= 36/3 = v
= v = +12cm
this is the case where the object is placed between focus and pole of concave mirror. the image formed here is behind the mirror and s enlarged....
CHEERS, ROHIT
Hey!
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Height of the object (h) = 3 cm
Distance of object from concave mirror (u) = -8 cm
Height of the virtual image formed (h') = 4.5
Let's find 'v' first =
- v/u = h'/h
v = - u × h'/h
v = - ( -8) × 4.5 / 3
v = 12 cm
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(i) Focal length of mirror = ?
1/f = 1/v + 1/u
1/f = 1/12 + 1/ -8
1/f = -1/24
1 × 24 = -f
24 = -f
f = -24 cm
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(ii) Position of image (v) = 12 cm
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(iii) Ray diagram - Refer pic
(Image is vertical , thus erect)
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Hope it helps...!!!
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