Question

an object 4 cm high is placed at a distance of 6 cm in front of a concave mirror of focal length 12 cm. Find the position of the image

Answer 1

Given:
after sign conventions:
f=-12cm
u=-6cm
h0=4cm
By mirror formula,
1/f=1/v+1/u
1/v=1/f-1/u
=1/-12 +1/6
=-1/12+1/6
=1/12
v=12cm
since object is placed between P and F , we get virtual and erect
m=-v/u
=-12/-6
=+2
also m=hi/h0
2=hi/4cm
hi=8cm

hence image is magnified , that is 8cm height.

Answer 2

Hulloa dear
Here it is.....