Question

an object 4 cm in size is placed at a distance of 25 cm from a concave mirror of focal
length 15 cm .Find the position nature and height of the image.​

Answer 1

Answer:

Image distance is= -37.5cm

and Height is-6cm

Explanation:

We have,u= -25 cm, f= -15cm, v=?

Mirror formula: 1/f=1/v+1/u

we put the values

1/-15=1/v+1/(-25)

1/v=1/-15 -1/25

we take the lcm and we get

-2/75

v= -75/2 =37.5

magnification formula= -v/u =h'/h

h'/4= - (-37.5)/-25

h'= -37.5×4 = -150

h'= -150/25

h'= -6 cm

i hope u will understand this. ..