Question

an object 4cm height is placed at a distance of 6cm in front of a concave mirror of focal length is 18 cm.Find the nature ,size and position of the object ​

Answer 1

Answer:

Given:

f=-12cm

u=-6cm

h0=4cm

By mirror formula,

1/f=1/v+1/u

1/v=1/f-1/u

=1/-12 +1/6

=-1/12+1/6

=1/12

v=12cm

since object is placed between P and F , we get virtual and erect

m=-v/u

=-12/-6

=+2

also m=hi/h0

2=hi/4cm

hi=8cm

Hence image is magnified , that is 8cm height.