Question

An object 4cm in size, is placed at 25cm infront of a concave mirror! So of focal length 15cm. At what distance from the mirror whould a screen be pa placed in order to obtain a sharp image?Find the nature and the size of the image m​

Answer 1

Answer:

Given,

Focal length, f=15cm

Object distance, u=25cm

Object height, h0=4cm

From mirror formula,

f1=v1+u1

−151=−251+v1

⇒v1=−151+251

v=−37.5cm

magnification, m=−uv=h0hi

⇒m=−−25(−37.5)=4hi

hi=−2537.5×4

hi