Question

The breaks applied to a car produce a negative acceleration of 60 m/s^2 .If the car takes 2 seconds to stop after applying the breaks .Calculate the distance it travels during this time .​

Answer 1

Answer:

60m

Explanation:

Given,

acceleration = -60m/s^-2 (since it's negative)

time taken = 2s

Final velocity = 0m/s (as it stops)

Finding u(initial velocity) :-

→ v = u + at

→ 0 = u + (-60)*2

→ 0 = u - 120

→ u = 120

Now, distance is given by :-

→ s = ut + ½.at²

→ s = 120 + ½(-60)(2)²

→ s = 120 - 60

→ s = 60m

Distance covered is 60m

Hope it helps!! : )

Answer 2

hope the above attachment will help u...

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