Physics, asked by DulquerSalman1533, 1 year ago

An object 4cm in size is placed at a distance of 25.0 cm from a concave mirror of focal length 15.0 cm . find the position nature and height of the image.

Answers

Answered by hawkings
0
height of the image will be 6 cm and position nature real and inverted
Answered by BendingReality
2

Answer:

\displaystyle \red{{ \text{h}_i=6 \ cm}

Explanation:

Given :

Object distance u = 25 cm

Focal length f = 15 cm

We have mirror formula :

1 / f = 1 / v + 1 / u

- 1 / 15 = 1 / v - 1 / 25

1 / v = 1 / 25 - 1 / 15

5 / v = 1 / 5 - 1 / 3

5 / v = ( 3 - 5 ) / 15

5 / v = - 2 / 15

v = - 75 / 2 = - 37.5 cm

We know :

h_i / h_o = - v / u

Where i and o represent image and object

h_i = - ( - 37.5)  × 4 / 25

h_i = 6 cm

Nature of the image are as :

Real , inverted and magnified.

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