An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm .find the position of image ,its nature and size
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Answered by
590
height of object=5cm
f=15 cm
u=-20cm
therefore,
1/v=1/f-1/u
=1/15+1/20
=7/60
so v =60/7
therefore height of image=60/7/20=3/7
so the image is virtual,erect and smaller in size by 3/7th of its original size
f=15 cm
u=-20cm
therefore,
1/v=1/f-1/u
=1/15+1/20
=7/60
so v =60/7
therefore height of image=60/7/20=3/7
so the image is virtual,erect and smaller in size by 3/7th of its original size
theekshna:
the formula you have used is only in the case of lenses.
No
In case of lens 1/v-1/u=1/f
And in that of mirror 1/u+1/v=1/f
sorry,but in my state board textbook they have given like that
sorry , i didn't see the formula properly in my book. i am really sorry.
It's okay
Answered by
332
here is your correct answer
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