An object 5 cm height plays its distance from a 20 cm from a convex lens of focal length 15cm
find a= image distance b=size of image c=nature of image D= draw ray diagram
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Object-size, h = + 5.0 cm;
Object-distance, u = – 20.0 cm;
Focal length, f = –15.0 cm;
Image-distance, v = ?
Image-size, h′ = ?
Mirror formula is (1/v) + (1/u) = 1/f
1/v = (1/f) − (1/u)
= (−1/15) + (1/20)
= −1/60
v = − 60 cm.
The screen should be placed at 60 cm from the mirror. The image is real.
Magnification m = h'/h = − v/u = 60/(– 20) = – 3
Height of the image h' = mh = (– 3)x5 = − 15 cm
The image in inverted and enlarged.
Object-distance, u = – 20.0 cm;
Focal length, f = –15.0 cm;
Image-distance, v = ?
Image-size, h′ = ?
Mirror formula is (1/v) + (1/u) = 1/f
1/v = (1/f) − (1/u)
= (−1/15) + (1/20)
= −1/60
v = − 60 cm.
The screen should be placed at 60 cm from the mirror. The image is real.
Magnification m = h'/h = − v/u = 60/(– 20) = – 3
Height of the image h' = mh = (– 3)x5 = − 15 cm
The image in inverted and enlarged.
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