Question

an object 5 cm high is placed at a distance of 60 CM in front of a concave mirror of focal length 10 cm find the position and the size of image

Answer 1

Answer:

Hey!

Refer the attachment for the step by step explanation

The final answer is :

Image is formed at 12 CM behind the mirror and size of image is -1 CM

Answer 2

The position of image is at 12 cm from the mirror and the size of image is 1 cm.

Explanation:

Given : Object distance : u = -60 cm

Focal length : f = -10  [For concave mirror]

To find : position image and the size of image.

Mirror formula : $\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$ , where v is the image distance.

For v , it will be : $\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}$

Substitute all values ,  we get

$\dfrac{1}{v}=\dfrac{1}{-10}-\dfrac{1}{-60}=\dfrac{1}{60}-\dfrac{1}{10}=\dfrac{1-6}{60}=\dfrac{-5}{60}\\\\\Rightarrow\ v=\dfrac{60}{-5}=-12\ cm$

Magnification = $-\dfrac{v}{u}=-\dfrac{h_i}{h_o}$

, where $h_i$ is the size of image.

Substitute all values , we get

$\dfrac{-12}{-60}=\dfrac{h_i}{5}\\\\\Rightarrow\ h_i=\dfrac{5}{5}=1$

Hence, the position of image is at 12 cm from the mirror and the size of image is 1 cm.

# Learn more :

An object 4 cm high is placed at a distance of 6 cm in front of a

concave mirror of focal length 12 cm. Find the position of the image

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