Question

An object 5 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, it's nature and size​

Answer 1

Answer:

An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. ... v = 60/7 = 8.6 cm.

Answer 2

$\huge{\mathfrak{\underline{\red{Answer!}}}}$

height of object=5cm

f=15 cm

u=-20cm

therefore,

1/v=1/f-1/u

=1/15+1/20

=7/60

so v =60/7

therefore height of image=60/7/20=3/7

so the image is virtual,erect and smaller in size by 3/7th of its original size