AN OBJECT 50cm TALL IS PLACED ON PRINCIPLE AXIS OF A CONVEX LENS . ITS 20 cm TALL IMAGE IS FORM ON THE SCREEN PLACED AT A DISTANCE OF 10cm FROM THE LENS CALCULATE THE FOCAl LENGTH OF THE LENS
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ho= 50cm
hi=20cm
v=10cm
f=??
hi/ho=v/u
20/50=10/u
20u=500
u=25cm
1/f=1/v - 1/u
1/f = 1/10- 1/25
1/f = 5-2/50
1/f = 3/50
hi=20cm
v=10cm
f=??
hi/ho=v/u
20/50=10/u
20u=500
u=25cm
1/f=1/v - 1/u
1/f = 1/10- 1/25
1/f = 5-2/50
1/f = 3/50
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