an object 5cm height is kept 25 cm away from converging lens of focal length 10 cm draw the ray diagram and the find the position, size and nature of the image formed.also find the power of lens
.i want only power of lens
Answers
Answer:
YOUR QUESTION....
An object 5 cm in length is held 25 cm away from converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and nature of the image formed.
Given,
Given,Height of object =5cm
Given,Height of object =5cmPosition of object, u=−25cm
Given,Height of object =5cmPosition of object, u=−25cmFocal length of the lens, f=10cm
Given,Height of object =5cmPosition of object, u=−25cmFocal length of the lens, f=10cmPosition of image, v=?
Given,Height of object =5cmPosition of object, u=−25cmFocal length of the lens, f=10cmPosition of image, v=?We know that,
Given,Height of object =5cmPosition of object, u=−25cmFocal length of the lens, f=10cmPosition of image, v=?We know that,v¹− u¹= f¹
v¹+ 25/1 = 10/1
1v¹= 10/1− 25/1
So,
v¹= 50/(5−2)
(5−2)
(5−2) That is,
(5−2) That is,v¹= 50/3
3So,
3So,v= 3/50
50
50 =16.66cm
50 =16.66cmThus, distance of image is 16.66cm on the opposite side of lens.
50 =16.66cmThus, distance of image is 16.66cm on the opposite side of lens.Now, magnification = v/u
That is,
That is,m= −25
That is,m= −2516.66
That is,m= −2516.66
That is,m= −2516.66 =−0.66
That is,m= −2516.66 =−0.66Also,
That is,m= −2516.66 =−0.66Also,m= height of object
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height of image
mage
mage
mage or
mage or−0.66=
mage or−0.66= 5cm
mage or−0.66= 5cmheightofimage
mage or−0.66= 5cmheightofimage
mage or−0.66= 5cmheightofimage
mage or−0.66= 5cmheightofimage Therefore, Height of image =3.3cm
mage or−0.66= 5cmheightofimage Therefore, Height of image =3.3cmThe negative sign of the height of image shows that an inverted image is formed.
mage or−0.66= 5cmheightofimage Therefore, Height of image =3.3cmThe negative sign of the height of image shows that an inverted image is formed.Thus, position of image is at 16.66cm on opposite side of lens.
mage or−0.66= 5cmheightofimage Therefore, Height of image =3.3cmThe negative sign of the height of image shows that an inverted image is formed.Thus, position of image is at 16.66cm on opposite side of lens.Size of image =−3.3cm at the opposite side of lens
mage or−0.66= 5cmheightofimage Therefore, Height of image =3.3cmThe negative sign of the height of image shows that an inverted image is formed.Thus, position of image is at 16.66cm on opposite side of lens.Size of image =−3.3cm at the opposite side of lensNature of image is real and inverted.
mage or−0.66= 5cmheightofimage Therefore, Height of image =3.3cmThe negative sign of the height of image shows that an inverted image is formed.Thus, position of image is at 16.66cm on opposite side of lens.Size of image =−3.3cm at the opposite side of lensNature of image is real and inverted.solution
mage or−0.66= 5cmheightofimage Therefore, Height of image =3.3cmThe negative sign of the height of image shows that an inverted image is formed.Thus, position of image is at 16.66cm on opposite side of lens.Size of image =−3.3cm at the opposite side of lensNature of image is real and inverted.solutionAnswered by AISHWARYA uRRfff ASH....
Explanation:
The answer u want is 2 D
Answer:
p= 10 dioptre
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