an object 5cm in length is held 25 cm away from converging lens of focal length 10 cm.draw the ray diagram and find the position, size and the nature of the image formed.
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Explanation:
F = 10CM
U = -25CM
H = 5 CM
(1/F) = 1/V - 1/U
1/V = 1/F + 1/U
= 1/10 + 1/-25
= 5 - 2 / 50
= 3 / 50
1/V = 50/3 = 16.67CM (APPROX)
HEIGHT OF THE IMAGE FROMED
h1 / h0 = v / u
h1 / 5 = 16.67 / - 25
h1 = - 3.33
debadutta15:
sorry i think u haven't look at the question properly i am asking for what was the nature of the image
plz edit ur answer.
okk sorry
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