Question

An object 5cm in length is held 25cm away from a converging mirror of focal length 10cm. Draw the ray diagram and find size, posi8and nature of the image formed. ​

Answer 1

See the attachment

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Answer 2

Answer :-

• The distance of the image from the mirror is 16.67 cm.
• The size of the image is 3.34 cm.
• The image is real, inverted and highly diminished.

Explanation :-

The given mirror is concave mirror (converging).

Given,

• Height of object (h) = 5 cm
• Distance of object (u) = -25 cm
• Focal length (f) = -10 cm

By using mirror formula,

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f} \\ = > \frac{1}{v} = \frac{1}{f} - \frac{1}{u} \\ = > \frac{1}{v} = \frac{ - 1}{10} + \frac{1}{25} \\ = > \frac{1}{v} = \frac{ - 5 + 2}{50} \\ = > \frac{1}{v} = \frac{ - 3}{50} \\ = > v = \frac{50}{ - 3} \\ = > v = - 16.67 \: cm$

Hence, the image is real.

Magnification,

$m = \frac{h</strong><strong>'</strong><strong>}{h} = - \frac{v}{u} \\ = > h</strong><strong>'</strong><strong> = - \frac{vh}{u} \\ = > h</strong><strong>'</strong><strong> = - \frac{( - 16.67) \times 5}{ - 25} \\ = > h</strong><strong>'</strong><strong> = - 3.34 \: cm$

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