Question

An object 5cm in length is placed at a distance of 20cm infront of a convex mirrror of radius ofcurvature of 30cm. Find the position of the image , its nature and size. Also draw the ray diagram of it.

Answer 1

u = - 20 cm

ho = 5 cm

R = + 30 cm ... (convex mirror)

The image is formed at a distance of 8.57 cm behind the convex mirror. Thus, it is virtual and erect.

Thus, the height of an image is 2 cm.

Thus, we can say that tha image is diminished.

Answer 2

Answer:

u = - 20 cm

ho = 5 cm

R = + 30 cm ... (convex mirror)  

begin mathsize 12px style straight f equals straight R over 2 equals 30 over 2 equals plus 15 space cm space left parenthesis convex space mirror right parenthesis

From space the space mirror space formula comma space we space get

1 over straight f equals 1 over straight u plus 1 over straight v

rightwards arrow 1 over straight v equals 1 over straight f minus 1 over straight u

rightwards double arrow 1 over straight v equals 1 over 15 minus fraction numerator 1 over denominator negative 20 end fraction

rightwards double arrow straight v equals 8.57 space cm end style

The image is formed at a distance of 8.57 cm behind the convex mirror. Thus, it is virtual and erect.

 

m space equals space minus space v over u space space

m space equals negative space space fraction numerator 8.75 over denominator negative space 20 end fraction space equals space 0.4 space

A l s o comma

m space equals space h subscript i over h subscript o space

0.4 space equals h subscript i over 5 space

h subscript i space end subscript space equals space 0.4 space cross times space 5 space equals space 2 space c m

 

Thus, the height of an image is 2 cm.  

Thus, we can say that the image is diminished.  

Explanation:

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