Question

please anybody answer this question​

Answer 1

Answer:

(cos^4 theta)/a + (sin^4 theta)/b = sin^theta / b or cos^theta /a

Step-by-step explanation:

We know , (cos^ 2 theta)/a = (sin^2 theta)/b

Then , We can write L.H.S as :

((cos^2 theta)^2)/a  + ((sin^2 theta)^2)/b

{(sin^2 theta x cos^theta ) + (sin^2 theta x sin^2 theta)}/b

Taking sin^2 theta common ...

{sin^2 theta(cos^2 theta + sin^2 theta)}/b

We know , sin^ theta + cos^2 theta = 1 so ,

sin^2 theta / b