An object 5cm in length is placed at a distance of 20cm in front of a convex mirror of radius of curvature 30cm.find the position of the image it's nature and size?
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Answer:
2.175 cm high, virtual and erect.
Explanation:
Formula:
v
1
+
u
1
=
f
1
Given,
v
1
+
(−20)
1
=
15
1
v
1
=
60
7
⇒v=
7
60
v=8.57≈8.6cm
The image is formed behind the mirror at a distance of 8.6 cm
m=
h
1
h
2
=−
u
v
→
5
h
2
=−
20
8.57
∴h
2
=2.175 cm
Thus the image is 2.175 cm high, virtual and erect.
Hence, this is the answer.
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