An object, 5cm in size, is placed 30cm in front of a concave mirror of focal length 15 cm. find the position, size and nature of the image formed. draw a ray diagram to show the image formation.
Answers
Answered by
45
Hello
here's your answer
As per question, size of a object, h = +5 cm;
focal length of the concave mirror, f = -15 cm
and object distance, u = -30 cm
1/v + 1/u = 1/f, hence, we have
1/v = 1/f - 1/u = 1/(-15)-1/(-30)
= -1/15+1/30 = -1/30
v = -30 cm
m = h'/h = -v/u
size of the image, h' = -v/u × h
= (-30)/(-30)×5
= -5cm
glad help you
it helps you
thank you,
@vaibhavhoax
#born with attitude
here's your answer
As per question, size of a object, h = +5 cm;
focal length of the concave mirror, f = -15 cm
and object distance, u = -30 cm
1/v + 1/u = 1/f, hence, we have
1/v = 1/f - 1/u = 1/(-15)-1/(-30)
= -1/15+1/30 = -1/30
v = -30 cm
m = h'/h = -v/u
size of the image, h' = -v/u × h
= (-30)/(-30)×5
= -5cm
glad help you
it helps you
thank you,
@vaibhavhoax
#born with attitude
Answered by
19
Hey mate...
here's ur answer
Height of the object ( h ) = +5 cm
focal length of the mirror (f) = -15 cm
Distance ( u ) = -30 cm
Using the formula......
1/v + 1/u = 1/f
1/v = 1/f - 1/u =
1/(-15)-1/(-30)
= -1/15+1/30 = -1/30
v = -30 cm
m = h'/h = -v/u
size of the image h' =
-v/u × h
= -30/(-30)×5
= -5cm
Hope it helps ❤️
here's ur answer
Height of the object ( h ) = +5 cm
focal length of the mirror (f) = -15 cm
Distance ( u ) = -30 cm
Using the formula......
1/v + 1/u = 1/f
1/v = 1/f - 1/u =
1/(-15)-1/(-30)
= -1/15+1/30 = -1/30
v = -30 cm
m = h'/h = -v/u
size of the image h' =
-v/u × h
= -30/(-30)×5
= -5cm
Hope it helps ❤️
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