Question

An object 5cm is kept infront of a convex mirror having radius of curvature 30cm at distance of 10cm.Calculate the position,size and features of image?
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Answer 1

Answer:

Explanation:

R = 30 cm  f = 15 cm u = 10 cm $h_o$ = 5 cm  ⇒$v = ? & h_i = ?$

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

-1/15 = 1/v - 1/10

1/v = -1/15+1/10 = 15-10/150 = 5/30 = 1/6

v = 6 cm

its a virtual image because object is placed between focal length and pole

$\frac{h_i}{h_o} = \frac{v}{u}$

hi = 6×5/10 = 3cm