Question

an object 5cm lenght placed at adistance of 20cm in front ofa convex mirror of radious of curvature 30cm find the position of the image​

Answer 1

Light

Given

Height of the object = 5cm

u = -20 cm

R = +30 cm

Therefore,

f = 15 m [ f = R/2]

We know that

(1/v) + (1/u) = 1/f

=> (1/v) + {1/(-20)} = 1/15

=> 1/v = (1/15) + (1/20)

=> 1/v = (4+3)/60

=> v = 60/7

=> v = 8.6 cm

So the object is 8.5 cm away from the pole

Also the image created is virtual and erect

That's it

Hope it helped

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