An object 6cm high is placed at a distance of 6 cm from a convex mirror of radius of
curvature 24 cm. Find the nature , position and size of the image.
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h = 6 cm.
u = - 6 cm.
R = 24 cm.
..f = 12 cm.
- Using formula
1/f = 1/u + 1/ v.
1/12 = 1/-6 +1/ v.
1/v = 1/12 + 1/6.
1+2/12 = 3/12
1/v = 1/4.
v = 4.
m = h'/ h = -v/ 4
h'/ 6 = -4/ -6
h' = 4/6 ×6
= 4 cm ⸻➤position of image.
hence , the image will be virtual, erect and diminished.
Hope it helps you..
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