An object 6cm in size is placed at 50 cm in front of a convex lens of focal length 30cm.At whay distance from the lens should a screen be placed in order to obtain a sharp image of the object? Find the nature and size of the image.Also, draw labelled ray diagram to show the image formation in this case.
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Height of object = +6 cm
Object distance = -50 cm
Focal length = +30 cm
Lens formula = 1/f = 1/v - 1/u
1/v = 1/f + 1/u
1/v = 1/30 - 1/50
= 5-3/150
= 2/150
Image distance = 150/2 = +75.5 cm
height of image = image distance
height of object object distance
h = 75.5 x 6
- 50
h = +9.06 cm
Hence image formed is virtual, erect, and magnified
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