Question

An object A of mass 4.2 kg and horizontal velocity 3.6 m s' moves towards
object B as shown in Fig. 1.
Object B of mass iš kg is moving with a horizontal velocity of
1.2 has towards object A. The objects collide and then both move to the right,
as shown in Fig. 2.
Object A has velocity v and object B has velocity 3.0 m s-
Calculate the velocity v of object A after the collision.
ii)
Determine whether the collision is elastic or inelastic.
State Newton's second law​

Answer 1

Answer:

Let a,d and n be the first term,common difference and number of terms of an AP respectively.

Now,

a

26

=a+25d=0 ...(1)

a

11

=a+10d=3 ...(2)

on doing (1)-(2) , we get

15d=−3

⇒d=

5

−1

On substituting the value of d in (1), we get

a+25×

5

−1

=0

⇒a=5

Again, a

n

=a+(n−1)d=

5

−1

On substituting the values of a and d, we get

5+(n−1)×

5

−1

=

5

−1

⇒(n−1)×

5

−1

=

5

−1

−5=

5

−26

⇒(n−1)=26

⇒n=27

Therefore,

d=

5

−1

,n=27

Answer 2

Answer:

PLEASE follow

Explanation:

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