Question

an object absorbs energy corresponding to wavelength 2400 angstrom and emits two radiations. if wavelength of one radiation is 6000 angstrom then what is the wave length of the other radiation??

Answer 1

Answer:

4000 Angstroms

Explanation:

Energy constant

incident energy= radiated energy

E = hc/wavelength

$\frac{1}{2400} = \frac{1}{6000} + \frac{1}{x} \\ \frac{1}{2400} - \frac{1}{6000} = \frac{1}{x} \\ x = \frac{2400 \times 6000}{6000 - 2400} \\ x = \frac{2400 \times 6000}{3600} \\ x = 4000 \: angs.$