Question

an object covers two equal distance with speeds v1 and v2 .what is average speed

Answer 1

let distance are x.

average speed = (x+x)/(x/u + x/v) = 2/(1/u+1/v)
= 2uv/(u+v)


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Answer 2

let the distance is S
so time with speed v1= S/v1
also time with speed v2= S/v2

so, the AVG speed= total distance/total time
ie. S/(S/v1 + S/v2)= v1× v2/(v1+v2)



hope you will understand