Question

An object dropped from a cliff fall with a constant acceleration of 10m/s. Find its speed 5s after it was dropped

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Speed\:after\:5\:sec=50\:m/s}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Acceleration(a) = 10 \: m/s^{2} \\ \\ \tt: \implies Time(t) = 5 \: sec \\ \\\red{\underline \bold{To \: Find:}} \\ \tt: \implies Speed \: at \: 5 \: sec = ?$

• According to given question :

$\tt \circ \: Initial \: speed = 0 \: m/s \\ \\ \tt \circ \: Acceleration = 10 \: m/s^{2} \\ \\ \tt \circ \: Time = 5 \: sec \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies v = 0 + 10 \times 5 \\ \\ \green{\tt: \implies v = 50 \: m/s} \\ \\ \blue{\bold{Some \: related \: formula}} \\ \orange{\tt \circ \: s = ut + \frac{1}{2} a {t}^{2} } \\ \\ \orange{\tt \circ \: {v}^{2} = u ^{2} + 2as }$

Answer 2

Step-by-step explanation:

Given -

acceleration = 10 m/s²

time = 5 seconds

To Find -

Speed at 5 seconds

According to the question,

u = 0 m/s (initial velocity)

a = 10 m/s²

t = 5 s

As we know that,

v = u + at

= v = 0 + 10 × 5

• = v = 50 m/s

Hence,

Speed of object after 5 s is 50 m/s.

Formula Used -

• v = u + at

Other formulas like this -

• s = ut + 1/2at²
• v² = u² + 2as

Here,

u = initial velocity

v = final velocity

a = acceleration

t = time

s = distance