An object dropped from a cliff falls with a constant acceleration of 10m/s². Find its speed 2s after it was dropped.
Answers
Answered by
101
a=10 m/s^2
u=0 m/s
t=2 s
So,
v=u+at
v=0+10*2
v=20/s
u=0 m/s
t=2 s
So,
v=u+at
v=0+10*2
v=20/s
Answered by
58
a=10m/s^2
u=0
t=2s
v=?
v=u+at (first equation of motion)
v=(0+10×2)m/s
v=20m/s
So, its speed after 2s of drop or final velocity is 20m/s
u=0
t=2s
v=?
v=u+at (first equation of motion)
v=(0+10×2)m/s
v=20m/s
So, its speed after 2s of drop or final velocity is 20m/s
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