Question

An object dropped from a cliff falls
with a constant acceleration of lom/s 2
Find its speed 5 s after it was dropped​

Answer 1

Answer:

u= 0

a= -10m/s²

t= 5s

v=??

using equation

v= u+at

v= 0+(-10)×5

v= -50m/s( velocity)

but speed will be 50m/s

Answer 2

Answer:

The velocity obtained by the object 5 seconds later would be 50m/s.

Explanation:

$a=10m/{s}^2$

$t=5s$

$u=0m/s$(As it would be at rest before dropping)

$v=?$

$1^st Equation of Motion:$

$v=u+at$

$v=0+(5*10)$

$v=50m/s$