Question

an object dropped from a cliff falls with a constant acceleration of 10 m /s². find its speed 2s after it was dropped.
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Answer 1

Given,

• An Object Dropped from a cliff falls with a Constant Acceleration of 10m/s².
• Time is  2 Seconds.
• Initial Velocity is 0.

To Find,

• Final Velocity of Object

Solution :

$\longrightarrow$We Know First Equation of Motion  :

$\bigstar \large{\boxed{\sf{v = u + at}}}$

Here,

• v - Final Velocity
• u - Initial Velocity
• a - Acceleration
• t - Time

Now Put the Value in this Equation :

$\longmapsto \sf{v = u + at}$

$\longmapsto \sf{v = 0 + (10) \times 2}$

$\longmapsto \boxed{\sf{v = 20\:m/s}}$

Therefore,

$\implies$ After 2 Second , Object Velocity will be 20m/s.

$\rule{200}2$

Answer 2

$\sf{\underline{Answer\::}}$

The object's speed after time period of 2 second would be 20 m/s.

$\sf{\underline{Explanation\::}}$

An object of certain mass is dropped from a certain height from a cliff with a constant acceleration of 10m/s², this actually says that the object falls with no change in it's acceleration during the fall.

What would the speed of the object be after 2 seconds from the time it was dropped?

We have the three equations of motion to make things simpler.

1. v = u + at
2. s = ut + ½at²
3. v² = u² + 2as

Now just choose the suitable one based on the data and relax xD

Here we can use the 1st one.

=> $\sf{v=u+at}$

=> $\sf{v=0+10(2)}$

=> $\sf{v=0+20}$

=> $\sf{v=20}$

So,we see that the speed the object would be travelling with after 2 second is 20 m/s.

PS : Never throw object especially when you are at your sweet home because mom may throw you then xD

Peace! :)