Physics, asked by Anonymous, 1 year ago

an object dropped from a cliff falls with a constant acceleration of 10 meter per second square find its speed and distance after 2 second

Answers

Answered by 5Vivek

$acceleration = \frac{change \: in \: velocity}{time} \\ a = \frac{v - u}{t} \\ since \: \: a = 10m {s}^{ - 1} ....u = 0 \: m {s}^{ - 1} ....t \: = 2 \: sec \\ 10 = \frac{v - 0}{2} \\ v = 20m {s}^{ - 1} \: \: \: speed \\ for \: distance \\ s = ut + \frac{1}{2} \times a {t}^{2} \\ solving \: this \: we \: get \\ s = 20metre$

Anonymous: bhai iska answer 40 meter hoga

5Vivek: then use the third equation of motion to solve second part

5Vivek: or u can use speed is equal to distance upon time

5Vivek: but i think this will not be the correct method to solve this because it neglect the speed change when object falls

Anonymous: ya you are right

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