Question

An object dropped from a cliff falls with a constant acceleration of 10 m/s2. Find its speed 5 S after it

was dropped.​

Answer 1

Answer:

50m/s²

Explanation:

a=u-v/t

v=u+at

v=0+10×5

v=50m/s²

Hope it helps :)

Answer 2

Answer:

Here,

• $a = 10ms^{ - 2}$
• t = 5 sec.

• u = ${0ms^{-2}}$

To find:—

• → v

${ \underline{\bold{We \: \: know \: \: that ,}}}$

$\large{ \boxed{ \mathtt {\bold{v \: = u +at}}}}$

$\implies \: v \: = 0 + 10 × 5$

$\implies \large{ \boxed{ \mathtt{ \color{red}\bold{v \: =50m {s}^{ - 2} }}}}$