An object dropped from a cliff falls with a constant acceleration of 10 meter per second square . Find its speed 2 seconds after ot was dropped
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Answered by
31
A=10m/s^2
u=0
t=2s
v=?
v=u+at (first equation of motion)
v=(0+10×2)m/s
v=20m/s
So, its speed after 2s of drop or final velocity is 20m/s
u=0
t=2s
v=?
v=u+at (first equation of motion)
v=(0+10×2)m/s
v=20m/s
So, its speed after 2s of drop or final velocity is 20m/s
Answered by
10
A=10m/s^2
u=0
t=2s
v=?
v=u+at (first equation of motion)
v=(0+10×2)m/s
v=20m/s
So, its speed after 2s of drop or final velocity is 20m/s
u=0
t=2s
v=?
v=u+at (first equation of motion)
v=(0+10×2)m/s
v=20m/s
So, its speed after 2s of drop or final velocity is 20m/s
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