Question

An object dropped from a cliff falls with a constant acceleration of 10 meter per second square . Find its speed 2 seconds after ot was dropped

Answer 1

A=10m/s^2
u=0
t=2s
v=?
v=u+at (first equation of motion)
v=(0+10×2)m/s
v=20m/s
So, its speed after 2s of drop or final velocity is 20m/s

Answer 2

A=10m/s^2
u=0
t=2s
v=?
v=u+at (first equation of motion)
v=(0+10×2)m/s
v=20m/s
So, its speed after 2s of drop or final velocity is 20m/s