An object falling freely from rest reaches ground in 2s. If acceleration due to gravity is 9.8 m s-2 the velocity of the object on reaching the ground will be:
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Answer:
19.6
Explanation:
s=ut+1/2at² here u=0 then s=1/2gt²
s=1/2×9.8×2²=19.6
we know that
v²=u²+2as u=0
v=√2×9.8×19.6=19.6
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