Question

The population of a town is 64000. if the angle birth date is 10. 7% and the annual death rate is 3.2 % calculate the population after 3 years

Answer 1

Answer:

79507

Step-by-step explanation:

Since the question states nothing about variation in the birth and death rate (which does vary in real situations of population mapping), we can consider the rates constant.

So if the population in i'th year is $n_i$ and initial population is $n_0$,

$n_{i+1} = n_i + (0.107)n_i - (0.032)n_i$

So initially i=0, so

$i_1 = (1.075)i_0\\i_2= (1.075)i_1 = (1.075)^2i_0\\i_3=(1.075)i_2 = (1.075)^3i_0=(1.075)^3(64000)$

Answer 2

Answer:

79507

Step-by-step explanation:

Population of a town = 64000

Given that birth rate for next 3 years = 10.7%

So,

Number of births in next 1 year =(64000×10.7%)

= 6848

Also given that death rate for next 3 years = 3.2%

Number of deaths in next 1 year = 64000×3.2% = 2048

So,

Population of the town in next 1 year= 64000+6848-2048

= 68800

Population of the town at the start of 2nd year = 68800

Number of births in 2nd year = (68800× 10.7%)

= 7362

Number of deaths in 2nd year = (68800×3.2%)

= 2202

So,

Population of the town in 2nd year= 68800+7362 - 2202

= 73960

Population of the town at the start of 3rd year = 73960

Number of births in 3rd year = (73960× 10.7%)

= 7914

Number of deaths in 3rd year = (73960×3.2%)

= 2367

So,

Outstanding population after 3 years = 73960+7914 - 2367

= 79507